2x^2+5mx+4m+1=0

Solution for 2x^2+5mx+4m+1=0 equation:

Simplifying
2x2 + 5mx + 4m + 1 = 0

Reorder the terms:
1 + 4m + 5mx + 2x2 = 0

Solving
1 + 4m + 5mx + 2x2 = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4m + 5mx + -1 + 2x2 = 0 + -1

Reorder the terms:
1 + -1 + 4m + 5mx + 2x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4m + 5mx + 2x2 = 0 + -1
4m + 5mx + 2x2 = 0 + -1

Combine like terms: 0 + -1 = -1
4m + 5mx + 2x2 = -1

Add '-2x2' to each side of the equation.
4m + 5mx + 2x2 + -2x2 = -1 + -2x2

Combine like terms: 2x2 + -2x2 = 0
4m + 5mx + 0 = -1 + -2x2
4m + 5mx = -1 + -2x2

Reorder the terms:
1 + 4m + 5mx + 2x2 = -1 + -2x2 + 1 + 2x2

Reorder the terms:
1 + 4m + 5mx + 2x2 = -1 + 1 + -2x2 + 2x2

Combine like terms: -1 + 1 = 0
1 + 4m + 5mx + 2x2 = 0 + -2x2 + 2x2
1 + 4m + 5mx + 2x2 = -2x2 + 2x2

Combine like terms: -2x2 + 2x2 = 0
1 + 4m + 5mx + 2x2 = 0

The solution to this equation could not be determined.